x趋于0是,((x^2)的立方根-根号下x)⼀x的极限是多少

2025-12-24 18:11:12
推荐回答(1个)
回答1:

[x^(2/3)-x^(1/2)]/x=x^(-1/3)-x^(-1/2)=x^(-1/2)·(x^1/6-1),
x趋于0时,x^(-1/2)趋于+∞,(x^1/6-1)趋于-1,
所以,x趋于0时,x^(-1/2)·(x^1/6-1)的极限是-∞.